Cannot shuffle a Range, but can shuffle Range.Inclusive

[mbuzdalov]

Scala 2.12.10:

scala> scala.util.Random.shuffle(1 to 10)
res0: scala.collection.immutable.IndexedSeq[Int] = Vector(8, 4, 7, 6, 3, 5, 10, 9, 1, 2)

scala> scala.util.Random.shuffle(1 until 10)
<console>:12: error: Cannot construct a collection of type scala.collection.AbstractSeq[Int] with elements of type Int based on a collection of type scala.collection.AbstractSeq[Int].
       scala.util.Random.shuffle(1 until 10)

Scala 2.13.1:

scala> scala.util.Random.shuffle(1 to 10)
res0: IndexedSeq[Int] = Vector(2, 8, 3, 7, 10, 6, 5, 4, 1, 9)

scala> scala.util.Random.shuffle(1 until 10)
                                ^
       error: Cannot construct a collection of type C with elements of type Int based on a collection of type scala.collection.immutable.Range.

There is definitely something wrong.

[lrytz]

scala> implicitly[scala.collection.BuildFrom[Range.Inclusive, Int, _]]
val res5: scala.collection.BuildFrom[Range.Inclusive,Int,Any] = scala.collection.BuildFromLowPriority2$$anon$11@64b70f41

scala> implicitly[scala.collection.BuildFrom[Range, Int, _]]
                 ^
       error: Cannot construct a collection of type Any with elements of type Int based on a collection of type scala.collection.immutable.Range.

[ausmarton]

I'm new to this dev community and found this issue interesting. As I was trying to understand the issue, I realised that untils return type is an abstract class while tos return type is a concrete type Range.Inclusive.

Would changing the return type of until to Range.Exclusive here be a step in the right direction?

def until(end: Int): Range.Exclusive = Range(self, end)

[som-snytt]

#8569
#6948

[ausmarton]

Thanks @som-snytt, should we close this issue given it's duplicate of #6948?

[dwijnand]

Yeah, I think so, following #8569's lead.

[dwijnand]

Duplicate of #6948