Closed
Description
Steps To Reproduce
Consider an example:
sage: x = var('x',n=3)
sage: f = sum(x); f
x0 + x1 + x2
sage: f.limit(x[1]=1)
Cell In[3], line 1
f.limit(x[Integer(1)]=Integer(1))
^
SyntaxError: expression cannot contain assignment, perhaps you meant "=="?
sage: f.limit(x[1]==1)
[...]
ValueError: call the limit function like this, e.g. limit(expr, x=2).
Expected Behavior
It should be possible to computing limit without confusing its argument with an assignment. It'd would be much safer to have an interface like .limit(x[1], 1)
, where the variable and its value are separated.
Actual Behavior
Sage thinks x[1]=1
is an assignment and gives an error.
Additional Information
I was able to compute the limit via the following very roundabout way:
sage: f.limit(**{str(x[1]):1})
x0 + x2 + 1
Environment
- OS: Ubuntu 24.04.1 LTS
- Sage Version: 10.5.beta6
Checklist
- I have searched the existing issues for a bug report that matches the one I want to file, without success.
- I have read the documentation and troubleshoot guide