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Remove misleading code example from The Guide #15899

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13 changes: 4 additions & 9 deletions src/doc/guide.md
Original file line number Diff line number Diff line change
Expand Up @@ -684,15 +684,10 @@ let x = (let y = 5i); // found `let` in ident position
The compiler is telling us here that it was expecting to see the beginning of
an expression, and a `let` can only begin a statement, not an expression.

However, assigning to a variable binding is an expression:

```{rust}
let x;
let y = x = 5i;
```

In this case, we have an assignment expression (`x = 5`) whose value is
being used as part of a `let` declaration statement (`let y = ...`).
Note that assigning to an already-bound variable (e.g. `y = 5i`) is still an
expression, although its value is not particularly useful. Unlike C, where an
assignment evaluates to the assigned value (e.g. `5i` in the previous example),
in Rust the value of an assignment is the unit type `()` (which we'll cover later).

The second kind of statement in Rust is the **expression statement**. Its
purpose is to turn any expression into a statement. In practical terms, Rust's
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