Closed
Description
Bug Report
Notice this while testing the master branch. I bisected the regression to
/CC @ilevkivskyi
To Reproduce
https://mypy-play.net/?mypy=master&python=3.11&gist=b8554f05b565ff448d1a291b3dbc38c3
from collections.abc import Callable
from typing import ParamSpec, Concatenate, TypeVar, Any
_P = ParamSpec("_P")
_R = TypeVar("_R")
class A: ...
a = A()
def a_func(
func: Callable[Concatenate[A, _P], _R],
) -> Callable[Concatenate[Any, _P], _R]:
def wrapper(_: Any, /, *args: _P.args, **kwargs: _P.kwargs) -> _R:
return func(a, *args, **kwargs)
return wrapper
def filter(a, *args):
...
x: Any
y: object
a_func(filter)
x = a_func(filter) # error
y = a_func(filter)Expected Behavior
no error
Actual Behavior
main.py:28: error: Argument 1 to "a_func" has incompatible type "Callable[[Any, VarArg(Any)], Any]"; expected "Callable[[A, VarArg(Any), KwArg(Any)], Any]" [arg-type]
main.py:28: note: This is likely because "filter" has named arguments: "a". Consider marking them positional-only
Found 1 error in 1 file (checked 1 source file)
Your Environment
- Mypy version used:
mypy 1.7.0+dev.c0906408c10d24d748711fa24be5befb2c794d4c (compiled: no) - Python version used:
3.11.5