Spread syntax with extends object type parameters

[ethanresnick]

TypeScript Version: 2.6.1

Code

function<T extends object>(it: T) {
    return { ...it };
}

Expected behavior:
No error

Actual behavior:
Error: Spread types may only be created from object types.

[sandersn]

T is a type parameter, which cannot be used to create a spread type. The object type constraint doesn't get around this rule.

If we ever add a first-class spread type this restriction will go away.