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Should the fuzzer compare references? #3378

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@kripken

Description

@kripken

Consider this:

(module
 (func $0
  (nop)
 )
 (func $1
  (nop)
 )
 (func "export" (result funcref)
  (ref.func $1)
 )
)

Running duplicate function elimination on this, it will merge $1 into $0. It will turn (ref.func $1) into (ref.func $0) as a result. But then the fuzzer will see that before opts this returned a reference to the name "1" and afterwards to "0" which looks like a bug.

But is it..? Calling the function will show no difference in behavior. OTOH, comparing references on the outside would notice a difference if we return (ref.func $0) from another funciton - before optimizations the two references are different, but not after.

If this is not a valid optimization, it seems like duplicate function elimination and other passes need to be very careful about any function whose reference is taken - similar to how they are careful about references to them in the table (but worse in some cases, as the table may be internal sometimes).

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